12x^2=920-80x

Solution for 12x^2=920-80x equation:

12x^2=920-80x

We move all terms to the left:

12x^2-(920-80x)=0

We add all the numbers together, and all the variables

12x^2-(-80x+920)=0

We get rid of parentheses

12x^2+80x-920=0

a = 12; b = 80; c = -920;
Δ = b2-4ac
Δ = 802-4·12·(-920)
Δ = 50560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{50560}=\sqrt{64*790}=\sqrt{64}*\sqrt{790}=8\sqrt{790}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-8\sqrt{790}}{2*12}=\frac{-80-8\sqrt{790}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+8\sqrt{790}}{2*12}=\frac{-80+8\sqrt{790}}{24}
$